1. C Generate 16 Digit License Key Code
2. C Generate 16 Digit License Key Number
3. C Generate 16 Digit License Key Numbers

Re: How to generate a random number of 16 digit?

Mar 08, 2010 12:56 AMkedarrkulkarniLINK

Rameezwaheed

Here is the Methods for creating Random Number

I want to generate a 16-Digit License Key (CD-Key as is normally called) for a product I am developing in Visual Studio 2005 with C#.Net. It's a rich-client application and follows a Client-Server architechture for Registration Process, where, the License Key is generated at. Generate a free temporary License Key This page allows non-donors to instantly generate free temporary License Keys for our software. If you have donated or purchased a License Key, please return to the main License Key page to retrieve your permanent Key. In my example: I am using Serial Key (16 digits), Incrementing int, and the word Alpha for the secret salt. This makes generating serial keys slow and cpu intensive, but makes validating them very fast. Adding A Product with License Codes. Auto-Generate: Selecting 'Auto-Generate' enables SendOwl to automatically assign a 16 character license that has the form XXXX-XXXX-XXXX-XXXX. In response to this call you should return a license key in plain text, with nothing else present.

public static string CreateRandomPassword(int PasswordLength)
{

<div mce_style='MARGIN-LEFT: 20px'>string _allowedChars = 'abcdefghijkmnopqrstuvwxyzABCDEFGHJKLMNOPQRSTUVWXYZ0123456789';

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Random randNum = new Random();
char[] chars = new char[PasswordLength];
int allowedCharCount = _allowedChars.Length;
for (int i = 0; i < PasswordLength; i++)
{ <div mce_style='MARGIN-LEFT: 20px'>chars[i] = _allowedChars[(int)((_allowedChars.Length) * randNum.NextDouble())];</div>}
return new string(chars);</div>

C Generate 16 Digit License Key Code

}

and also try the below with GUID

public string GetRandomPasswordUsingGUID(int length)
{
// Get the GUID
string guidResult = System.Guid.NewGuid().ToString();
// Remove the hyphens
guidResult = guidResult.Replace('-', string.Empty);
// Make sure length is valid
if (length <= 0 length > guidResult.Length)
throw new ArgumentException('Length must be between 1 and ' + guidResult.Length);
// Return the first length bytes
return guidResult.Substring(0, length);
}

i think this is not the solution for u r scenario...

C Generate 16 Digit License Key Number

this will create random number which will be alphanumeric. and u want random number to be divisible by 10 (so, number should be numeric).

if u want account no. to be always divisible by 10, then why dont u set identity column as

createtable usertable( accountNo bigint identity(1000000000000000,10)primarykey,
accountInfo varchar(30))

every time new account number will be created by adding 10 in previous number.

or u can use configuration table (database table where generally global configuration of application are stored) and set last created account number there. like this

1) set some number in config table.

2) retrieve that number. add 10 to it. pass it to luhn algoreithm.

C Generate 16 Digit License Key Numbers

3) finally u will get proper account no. from luhn algorithm

4) update last created account no in configuration table.

hope this helps....